Then what will be the minimum hours taken by the second tap to drain this tank ?

Question

Three taps together drains a tank in 5 hours.
If first tap drains this tank in 10 hours alone.
Then what will be the minimum hours taken by the second tap to drain this tank ?

Answer 1

Answer: 10 Hrs

Amount of water drained by three taps = 1/5 = 0.2 i.e 20%
Amount of water drained by 1st tap = 1/10 = 0.1 i.e 10%
let x and y be time taken by 2nd and 3rd tap respectively,

==> 1/x + 1/y + 0.1 = 0.2
1/x + 1/y = 0.1
if we assume 3rd tap drains neglegible amount of water,
then, 1/x = 0.1 ==> x = 10 hrs