If the work done by (x-1) men in (x+1) days is to the work done by (x+2) men in (x-1) days are in the ratio 9 : 10. Can you calculate the value of x ?
work done in first case = (x - 1) (x + 1) work done in second case = (x + 2) (x - 1) ration of the above is : (x - 1) (x +1) / (x + 2) (x - 1) = 9 / 10 (x + 1) / (x + 2) = 9 / 10 10x + 10 = 9x + 18 10x - 9x = 18 - 10 x = 8 So the value of x is 8
(x-1)(x+1)/(x-1)(x+2)=9/10 so that value of x is =8
Can you solve this equation to get the value of x?
(2^x) (30^3) = (2^3) (3^3) (4^3) (5^3)
The function f(x) is differentiable, continuous, and f(x) ≠ 0 for all values of x in the interval [4, 8]. Calculate f(6) given that f(4) = 1/4, f(8) = 1/2,
Suppose:
ax + by = 5 ax2 + by2 = 10 ax3 + by3 = 50 ax4 + by4 = 130
Calculate the value of:
13(x + y – xy) – 120(a + b) = ?
