What is the four-digit number in which the first digit is one third the second, the third is the sum of the first and second, and the last is three times the second?
first=f,second=s,third=T,Last=L f=s/3 T=f+s L=3s since s is divisible by 3,so s can be 3,6,9 Taking s=3 f=1 T=3+1=4 L=3*3=9
so answer is 1349
Answer is 1349
obviously the solution is 1349
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