The sum of ages of Mac and Jabi is 26 times the difference of their ages. Maximum possible difference of the ages is 10 years. How many possibilities for ages of the two persons are possible. (Ages are taken in integers.)
5 is the answer x+y=26(x-y) => 25x=27y => x/y= 27/25 difference is 2. so possible values could be 27,28 or 54,50 or 81,75 or 108,100 and 135,125 So, answer is 5
There are two buildings P and Q. If 35 persons sent from P to Q, then the number of persons in each building is the same. If 60 persons are sent from Q to P, then the number of persons in P is double the number of persons in Q. How many persons are there in building in P?
The present ages of two persons differ by 35 years. 3 years later, the elder one would be 4.5 times as old as the younger one. What is the present age of the elder person?
The present ages of two persons differ by 16 years. 3 years ago, the elder one was 3 times as old as the younger one. What is the present age of the elder person?
How many ways are possible to arrange 4 boys and 3 girls for a dinner, if there are two straight benches of capacity 5 and 2 persons for their sitting?
