3 red, 2 white and 3 green balls are available in a bag. 2 balls are drawn one by one from the bag.
What will be the probability of one ball is white & other is green?
Probability of first ball having white color = 3/8 and that of second ball having green color = 3/7 so probability = 2/8 * 3/7 = 6/56 no of methods to make arrangement = 2*1 = 2 (WG and GW) so net probability = 6/56 * 2 = 12/56 = 3/14
A bag has 100 balls out of which there is one green ball. 50 balls are randomly selected. What is probability that the green ball is selected.
A bag contains 5 green, 7 red and 4 white balls. If three balls are drawn one after the other with replacement, then what is the probability of getting balls of same colour?
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
A bag contains 5 white, 4 red and 3 black balls. A ball is drawn at random from the bag, what is the probability that it is not black?
There are two bags. First contain 10 white balls and other contain 8 red balls. One ball from any bag shifted to other bag at random. What will be the probability the second ball taken after first event would be red ? First event is to drawn first ball.
