There is a square of a particular number which when doubled, becomes 7 more than its quarter. Can you find the number?

Question

There is a number, the second digit of which is smaller than its first digit by 4, and if the number was divided by the digit's sum, the quotient would be 7.
Can you find the number?

Answer 1

The number is 2
Suppose the number is x.
From the given statement , 2X^2 - 7 = X^2 /4
That solves to 8x^2 - 28 = X^2 ==> X^2 = 4

So X = + /- 2