If x, y, z are 3 non zero positive integers such that x+y+z = 8 and xy+yz+zx = 20, then What would be minimum possible value of x*y^2*z^2
Values are 4,2,2 So answer is 64
Solving we got X*y^2*z^2 = X(x^2-8x+20) Since X has a positive value and we have to get minimum then putting X=1 We get 169 So 169 is the answer
ans is 64, for minimum value, x,y& z will be 4,2 &2,
4, 2, 2 answer 64
2, 3+sqr(5), 3-sqr(5) The answer is 32
x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be
The temperature on a unit sphere x^2 + y^2 + z^2 = 1, is given by a temperature distribution
T(x,y,z) = 50.(xy + yz)
What is the temperature difference between the coldest and warmest point on the sphere?
