Ticket numbered from 1 to 20 are mixed up and a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 7 ?
multiples of 3 3 6 9 12 15 18
multiples of 7 7 14
all possible outcomes 6+2=8
probability= 8/20 =2/5
From 1 to 20 numbers divisible by 3 are 6 by 7 are 2. So, favourable outcomes are 8 out of a possible 20 outcomes Probability = favourable outcomes / possible outcomes = 8/20 = 2/5 = 0.4
p(E) = 8c1 / 20c1 = 8/20.....
multiples of 3= 3 , 6 , 9 , 12 ,15 , 18..
multiples of 7 = 7 , 14,,,,,
Tickets numbered 1 to 37 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 10?
The tickets numbered from 99 to 116 are mixed up and then a ticket is drawn at random. What is the probability that the ticket has a number which is a multiple of 3 or 5?
The tickets numbered from 1 to 30 are mixed up then a ticket is drawn at random. What is the probability that the ticket has a number which is a multiple of 3 or 5?
Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn bears a number which is a multiple of 3.