199 (a*b*2)+(a+b)=c 9*10*2=180 180+9+10=199
(a+b)*b+a
a=9 ,b=10
199
2*n^2 +4*n +1 = 162+ 36+ 1 = 199, where n= 9
(1+2)*2 + 1 = 7 (3+4)*4 + 3 = 31 (5+6)*6 + 5 = 71 (7+8)*8 + 7 = 127 (9+10)*10 + 9 = 199
Ans :- 199
1+2= 1+(1+2)*2 = 7 3+4= 3+(3+4)*4 = 31 5+6= 5+(5+6)*6 = 71 7+8= 7+(7+8)*8 = 127 9+10= 9+(9+10)*10 = 199
so, 199 is the answer.
y*y+x*x+y+(y-2) 2*2+1*1+2+(2-2)=7 4*4+3*3+4+(4-2)=31 6*6+5*5+6+(6-2)=71 8*8+7*7+8+(8-2)=127 10*10+9*9+10+(10-2)=199
a*a+b*b + (a+b-1)=9*9+10*10+(1+10-1)=181+18=199
here right side= a(a+2)+b^2
1+2= 1*3+2^2=3+4=7
3+4=3*5+4^2=15+16=31
5+6=5*7+6^2=35+36=71
hence 9+10=9*11+10^2=99+100=199 answer=199
If 5 + 4 => 9 3 + 5 => 9 9 + 1 => 9 1 + 6 => 8 4 + 2 => 8 1 + 7 => 7 5 + 6 => 6 3 + 7 => 3 7 + 0 => 0 Then 8 – 1 => ??
Solve if you are genius?