The ans is 19
Numbers are 15 & 4
19 The two numbers are: 4 & 15
x-y=11 x*y=60{ x=60/y} (60/y)-y=11 y^2+11y-60=0 (y-4)(y-15)=0 y=4,y=15 therefore the two numbers are 4 and 15 then the sum of two numbers are 19.
LCM of two numbers is 60 times their HCF. If sum of LCM and HCF is 549. If one number is 45 then what is the other number?
The sum of 3 single digit numbers is 15 less than their product . If we subtract 2 from first given number then sum of these numbers will become 7 more than their product. Then what will be the product of given 3 numbers?