From the question 6A = 8B = 10C = k
So A = k/6, B = k/8, and C = k/10
Therefore A : B : C = k/6 : k/8 : k/10
or ratio is 20:15:12
let x = k/6 = k/8/ = k/10
so its 20:15:12
ex: 6*20 = 8*15 = 10*12 = 120
The age of a father 10 years ago was thrice the age of his son . Ten years hence, the father's age will be twice that of his son. What is the ratio of their present ages?
School A has boys to girls in the ratio 5:6 and school B has girls to boys in the ratio 8:7. If the number of students in school A is at least twice as many as the number of students in school B, what is the minimum percentage of boys when both schools are considered together?