main() { int a=2; printf("%d ",(++a)*(a+=2)* (a=5)); }
please give output , with explanation!!!
This code will not compile and give the following "error called object '++a' is not a function" Don't know what you are trying to do, but avoid writing this type of tricky code which will give different output on different compiler.
#include<stdio.h> int main() { int n; for(n = 7; n!=0; n--) printf("n = %d", n--); getchar(); return 0; }
void main(){ int i=320; char *ptr=(char *)&i; printf("%d",*ptr); }
Please provide your explanation also?
#include<stdio.h> int main(){ int s=2,*r=&s,**q=&r,***p=&q; printf("%d",p[0][0][0]); return 0; }
Please provide the explanation of the answer also.
See the following code
void main(){ float a=5.2; if(a==5.2) printf("Equal"); else if(a<5.2) printf("Less than"); else printf("Greater than"); }
Expected output is equal but we does not get same why?
