Question

Write a C logic that stores 3 numeric values ranges 0 to 9 digits into 10 bits....eg 999 to fit into 10 bits

Comments

10 binary bits can contain 0-1023 so we can simply mod the number by 1000 convert into binary shift 3 bit and repeat the process...

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can you elaborate...send code

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Its same as BCD where u are converting 1 digit to four binary bits. The change would be 3 digits would be converted to 10 binary bits. I will send the code tomorrow.

Answer 1

Try something like this (obviously it will hit the overflow so you need to consider the overflow)

long long int decimal_binary(long int n) 
{
    long long int rem, i=1, binary=0;

    while (n!=0)
    {
        rem=n%2;
        n/=2;
        binary+=rem*i;
        i*=10;
    }

    return binary;
}

unsigned long long convert(unsigned long long int a)
{
   if (a<1000)
   {
     return decimal_binary(a);
   }
   else
   {
        return ((convert(a/1000))<<10)+(convert(a%1000));
   }
}