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Which order of loops is fastest in matrix multiplication and why ?

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for(i=0;i<n;i++)
  for(j=0;j<n;j++)
     for(k=0;k<n;k++)
        C[i][j]+=A[i][k]*B[k][j];

In this algorithm, there are 6 combinations of loops : the one given above is ijk. The others are ikj,jki,jik,kij and kji. Which one executes the fastest and why?

posted Jun 29, 2016 by anonymous

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Similar Questions
0 votes

suppose

A(n,m) = 
1 2 3         
4 5 6                            
7 8 9

and 

B(p, q) = 
1 1
1 1

What is best method to find min of square of difference of sub-matrices of A and B e.g.

sub-matrices of A =

1 2    |     2 3   |    4 5    |   5 6
3 4    |     5 6   |    7 8    |   8 9

Difference of first sub-matrix of A with B =

(1-1)  (2-1)    = |     0 1
(3-1)  (4-1)      |     2 3

sum of square of elements = 0*0 + 1*1 + 2*2 + 3*3 = 14

similar steps for other sub-matrices of A

Please suggest looking for an alternate method or algorithm which has time complexity less than O(n*m*p*q)

+3 votes

Say we have two matrix of m*n and n*t.
Any sample code in C/C++ along with the algorithm would be helpful.

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