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C++ : How a programmer can define overloaded type casting operator ?

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C++ : How a programmer can define overloaded type casting operator ?
posted Sep 11, 2016 by Neelam

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1 Answer

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It is very simple, use the following definition:

operator () { return }

Here, desired type can be built-in data type or user defined data type.
For example: Assume you have two classes one if known as rupee and the other one is paisa.
rupee rupeeObject(5);
paisa paisaObject(rupeeObject); /* This will not work unless you have overloaded type casting operator for paisa class in rupee class.

answer Sep 16, 2016 by Vimal Kumar Mishra
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