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How to create a Scala/Akka Actor whose constructor requires arguments?

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How to create a Scala/Akka Actor whose constructor requires arguments?
posted Sep 19, 2016 by Dominic

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1 Answer

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Create the actor using the syntax shown here, where HelloActor takes one constructor parameter:

val helloActor = system.actorOf(Props(new HelloActor("Fred")), name = "helloactor")

Discussion

When creating an actor whose constructor takes one or more arguments, you still use the Props class to create the actor, but with a different syntax than when creating an actor whose constructor takes no arguments.

The following code demonstrates the difference between creating an actor with a no-args constructor and an actor that takes at least one constructor parameter:

// an actor with a no-args constructor

val helloActor = system.actorOf(Props[HelloActor], name = "helloactor")

// an actor whose constructor takes one argument

val helloActor = system.actorOf(Props(new HelloActor("Fred")), name = "helloactor")

To demonstrate these differences, the following source code is a modified version of the example in Recipe 13.1. Comments are included in the code to highlight the changes:

import akka.actor._

// (1) constructor changed to take a parameter

class HelloActor(myName: String) extends Actor {
    def receive = {
        // (2) println statements changed to show the name
        case "hello" => println(s"hello from $myName")
        case _       => println(s"'huh?', said $myName")
    }
}

object Main extends App {
    val system = ActorSystem("HelloSystem")
    // (3) use a different version of the Props constructor
    val helloActor = system.actorOf(Props(new HelloActor("Fred")), name = "helloactor")
    helloActor ! "hello"
    helloActor ! "buenos dias"
    system.shutdown
}

As shown in this example, if your actor takes more than one argument, include those arguments in the constructor call. If the HelloActor constructor required both a first and last name, you’d specify them like this:

Props(new HelloActor("John", "Doe")), name = "helloactor")
Remember that an actor instance is instantiated and started when the actorOf method is called, so the only ways to set a property in an actor instance are:

By sending the actor a message
In the actor’s constructor
In its preStart method

answer Sep 22, 2016 by Karthick.c
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