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How to flatten only one sub list of list of lists using python?

+2 votes
361 views

How can I flatten just a specific sublist of each list in a list of lists?

So if I had this data

[ ['46295', 'Montauk', '3', '60', '85', ['19', '5', '1', '0 $277790.00']],
 ['46295', 'Dark Eyes', '5', '59', '83', ['6', '4', '1', '0 $105625.00']],
 ['46295', 'Machinegun Jubs', '6', '53', '77', ['6', '2', '1', '1 $71685.00']],
 ['46295', 'Zara Bay', '1', '53', '77', ['12', '2', '3', '3 $112645.00']]]

How can I make it be

[ ['46295', 'Montauk', '3', '60', '85', '19', '5', '1', '0 $277790.00'],
 ['46295', 'Dark Eyes', '5', '59', '83', '6', '4', '1', '0 $105625.00'],
 ['46295', 'Machinegun Jubs', '6', '53', '77', '6', '2', '1', '1 $71685.00'],
 ['46295', 'Zara Bay', '1', '53', '77', '12', '2', '3', '3 $112645.00']]

Been looking around but most solutions just entirely flatten everything. This was popular on SO but yeah it flattens everything I want to be more selective

def flatten(lst):
 for elem in lst:
 if type(elem) in (tuple, list):
 for i in flatten(elem):
 yield i
 else:
 yield elem

What I am thinking is that if for each list the sublist should be at index 1, so

[0][1]
[1][1]
[2][1]

for item in list:
 item[1] - somehow flatten.

Any Idea or pointer?

posted Mar 1, 2017 by anonymous

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