struct marks { int a:1; int b:2; }; int main() { struct marks obj={1,6}; printf("%d %d\n",obj.b,obj.a); }
This question is not as simple as it looks. What I interpreted that first field a and second field b both are signed integer type. If I consider a short int as 1 byte then its left most bit would signify (+/-) based on either left most bit is 0 or 1. In this case though only one bit is reserved for member "a "but this bit would be considered for signed/unsigned also that's why when value 1 is assign to "a" and when it is printed it shows as -1. Same concept of member "b" also.
See the following code
void main(){ float a=5.2; if(a==5.2) printf("Equal"); else if(a<5.2) printf("Less than"); else printf("Greater than"); }
Expected output is equal but we does not get same why?
Write a C code for the logic - input: string, strong output: strng
Result should be stored in new linked list.
