How to Generate Odd Numbers in Parallel using LINQ in C#?

1 Answer

This C# Program Generates Odd Numbers in Parallel using LINQ. Here it Provides a set of methods for querying objects that implement ParallelQuery{TSource} to generate odd numbers in parallel.
Here is source code of the C# Program to Generate Odd Numbers in Parallel using LINQ. The C# program is successfully compiled and executed with Microsoft Visual Studio. The program output is also shown below.

/*
 *  C# Program to Generate Odd Numbers in Parallel using LINQ
 */
using System;
using System.Linq;
using System.Collections.Generic;

class Program
{
    static void Main(string[] args)
    {
        IEnumerable<int> oddNums = ((ParallelQuery<int>)ParallelEnumerable.Range(20, 2000))
        .Where(x => x % 2 != 0)
        .Select(i => i);
        foreach (int n in oddNums) { Console.WriteLine(n); }
        Console.ReadLine();
    }
}

Here is the output of the C# Program:

answer Jun 26, 2017 by Shivaranjini

Similar Questions

–1 vote

How to List Odd Numbers from a List of Integers using LINQ Query in C#?

+2 votes

this code about Using lists to store data in and retrieve data from.,and Using LINQ to query an array in c#

Develop a C# Windows Form Application that allows users to do all of the following.
Read a List of patient's information from a text file (*.txt), the input text file is selected from the Open File Dialog.
Your program should accept any text file with the following format:
a. The file contains columns with Basic information about patients.
b. Columns may be separated by spaces and/or tabs.
c. The first line in the file is the column header.
d. After the header, each line represents a Patient (name, address, phone#, Bdate, gander ,wheight, height and blood type).
e. Successfully imported patients are displayed on a data grid view in a second form and added to a patient list.

The user will be able to display on The Grid view :
a) Female patients.
b) Patients with age<45 year. c) Save Over weighted patients on a text file .  Note: To find over weighted patients you have to calculate the BMI value. BMI=Weight/ (Height*Height). If BMI <18.5 >>>>> under weighted.
18.5<=BMI<=25 >>>>>>>Normal.
BMI>25 >>>>>>>>>>>> Over Weighted.

–1 vote

How to List out Even Numbers from a List of Integers using LINQ in C#?

0 votes

How to generate dwg file in C#?

0 votes

If given an array of ints, how to write a C# method to total all the values that are even numbers?

How to Generate Odd Numbers in Parallel using LINQ in C#?

Your comment on this post:

1 Answer

Your comment on this answer:

Your answer

Preview