How can I print function name?

Question

I have a function pointer that contains the address of function. I do not want any linux function. I want to compile my code with gcc without any option.
gcc -g my_code.c only.

Answer 1

int (*funPtr)(int,int);
int testFunction(int a, int b)
{

   printf("function:%s\n",\__func__);
    //Function code
}
int main()
{
        funPtr=testFunction;
        funPtr(0,0);
        return 0;
}

I am not sure ,If you are looking for this.

Comments

Thanks Sony.
But I have function pointer only.
The pointer is same and at run time a function is being bound  based on code flow . There are lots of function in code Which is being bound I do not know.
So I do not know where to add "printf("function:%s\n",\__func__);"