How to access command line arguments in shell script?

Question

I have some unique requirement, where I need to do something like this -
1. My script takes the argument as file name which is absolute filename.
2. I need to separate the filename and directory from this absolute file name for the further processing.

Any suggestions -

Answer 1

The arguments are stored in variables with a number in the order of the argument starting at 1

First Argument: $1
Second Argument: $2
Third Argument: $3
Example

command: ./script.bash alpha beta gamma

Variables: $1=='alpha'; $2=='beta'; $3=='gamma'

The variable $0 is the script's name. The total number of arguments is stored in $#. The variables $@ and $* return all the arguments.

Comments

Thanks Vikas, it was helpful