How to calculate wind chill index for the given temprature and wind speed.

Question

The wind chill index (WCI) is calculated from the wind speed (v) in miles per hour and the temprature (t) in
fahrenheit . three formulas are used . depending on the wind speed :
if(0<=v<=4)then WCI=t
if(v>=45) then WcI =1.6t-55
otherwise , WCI=91.4 + (0.0203v - 0.304(v)^1/2 - 0.474)

write a program that prompt the user to insert the wind speed (v) in miles per hour format and prompt the user to insert wind temprature on fehrenhite then calculate the wind chill index

Answer 1

Providing only the function, I leave creating main function and calling this appropriately to you.

float func_wci(float t, float v)
{
  if ((v >= 0) && (v <=4))
      return t;
  if (v >= 45) 
      return 1.6*t -55;
  else
      return (91.4 + (.0203*v - .304*(v)^.5 - .474));
}

Comments

i want it without function
float v , t , WCI;
    cout<<"please enter value for wind speed in miles per hour "<<endl;
    cin>>v;
    cout<<endl;
    cout<<"please enter value for wind temprature in fehrenhite "<<endl;
    cin>>t;
    cout<<endl;


    if((v>=0) && (v<=4))
   
        WCI = t;
    else if(v>=45)
        WCI=1.6*t-55;
    else
        WCI = 91.4 + (91.4 - t)* (0.0203 * v^(1/2)-0.474);*/


this is true or what ?!!

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Try this it should work
int main()
{
    double v , t , WCI;
    cout<<"please enter value for wind speed in miles per hour "<<endl;
    cin>>v;
    cout<<endl;
    cout<<"please enter value for wind temprature in fehrenhite "<<endl;
    cin>>t;
    cout<<endl;


    if((v>=0) && (v<=4))    
        WCI = t;
    else if(v>=45)
        WCI=1.6*t-55;
    else
        WCI = 91.4 + (91.4 - t)* (0.0203 * pow(v, .5)-0.474);

    cout << WCI;
    return 0;
}