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Do we have a better method, capable to inspect each RB?

+1 vote
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As we know Per Resource Blocks (RB) SINR from UE report. I know that an UE reports all the RBs SINR as quick as possible (maybe each subframe period, that is 1 ms). I’m thinking of the Higher Layer-configured subband CQI report since it’s the most capable of inspecting the RBs status as I saw in 3GPP 36.213 Table 7.2.1-1. I’m interested in FDD; unfortunately the least “RB contiguous number” is 4 as in Table 7.2.1-3. Do we have a better method capable to inspect each RB?

posted Jun 16, 2014 by Nimish

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1 Answer

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The least RB contiguous number is defined in this table that you mentioned 7.2.1-1 of 36.213. From the standard point of view that’s the only possibility (meaning the lowest granularity possible). This is due to the tradeoff that the standard needed to take between the accuracy (high granularity of the reports) and feedback overhead (low granularity of the reports). While designing a practical system, you need to take into account these tradeoffs

answer Jun 17, 2014 by Riteshwar
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Hi All,

It is mentioned in different websites that in LTE max. of 8 DRB can be established per UE. But as per page 652 of 36.331 V13.2.0, the max no. of DRB is 11.
"maxDRB INTEGER ::= 11 -- Maximum number of Data Radio Bearers"

Based on what source are we saying that max. DRB in LTE is 8 and not 11.

It was mentioned in one of the old threads the following:

If EPS bearer ID is = x +4 ;
Then
DRB ID = x;
Logical Channel ID = x + 2

I found the above relationship of DRB ID & EPS Bearer ID to be true for one of the eNB vendors but not for another one.

Example:
EPS ID is 5 and DRB ID is 4 instead of 1. Can somebody comment in this?
NOTE : All these ranges is with respect to DRB establishment

EPS Bearer ID Range is INTEGER (0..15) (But 0-4 is reserved so we use starting from 5 )
DRB ID Range is INTEGER (1..32) (As in LTE max 8 DRB can be established per UE so we use from 1-8)
Logical Channel ID range for DRBs is INTEGER (3..10) ( For for DRB1 we use 3 as logical channed ID)

Thanks

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