c++: Is it possible to call constructor and destructor explicitly?

Question

explain the scenario with example?

Answer 1

Yes, it is possible to call special member functions explicitly by programmer. Following program calls constructor and destructor explicitly.

#include <iostream>
using namespace std;

class Test
{
public:
    Test()  { cout << "Constructor is executed\n"; }
    ~Test() { cout << "Destructor is executed\n";  }
};

int main()
{
    Test();  // Explicit call to constructor
    Test t; // local object
    t.~Test(); // Explicit call to destructor
    return 0;
}

Output:

Constructor is executed
Destructor is executed
Constructor is executed
Destructor is executed
Destructor is executed

When the constructor is called explicitly the compiler creates a nameless temporary object and it is immediately destroyed. That’s why 2nd line in the output is call to destructor.