What is the use nonlocal keyword in python?please explain with example?

Answer 1

The nonlocal statement causes the listed identifiers to refer to previously bound variables in the nearest enclosing scope.

See the following examples without and with nonlocal

>>> def outer():
       x = 1
       def inner():
           x = 2
           print("inner:", x)
       inner()
       print("outer:", x)

>>> outer()
inner: 2
outer: 1

To this, using nonlocal:

>>> def outer():
       x = 1
       def inner():
           nonlocal x
           x = 2
           print("inner:", x)
       inner()
       print("outer:", x)

>>> outer()
inner: 2
outer: 2