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Is it possible to know, which scheduling does JVM uses to schedule a Thread?

+1 vote
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As JVM uses the primitive or time slicing scheduling techniques for thread scheduling. Is it possible to know our exiting JVM using which technique for thread scheduling?

posted Aug 10, 2015 by Prakash Singh

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1 Answer

+1 vote

JVM is a specification and there are multiple implementations of it (OpenJDK version and the Sun version)

My guess:
A JVM should simply use the underlying threading mechanism provided by the OS, which would imply POSIX Threads (pthreads) on UNIX (Mac OS X, Linux, etc.) and would imply WIN32 threads on Windows. Typically, those systems use a round-robin strategy by default.

answer Aug 10, 2015 by anonymous
Similar Questions
+2 votes
import java.util.ArrayList;
import java.util.List;

public class ThreadB extends Thread {
    private static List<String> list1   = new ArrayList<String>();
    private static List<String> list2   = new ArrayList<String>();
    private static final Object mutex   = new Object();

    public void run() {
        try {
            sleep(2000l);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        synchronized (mutex) {
            list1.add("Hello");
            System.out.println("Added for 1   " + list1.size());
            list2.add("Added for 2");
            System.out.println("Added for 2   " + list2.size());
            mutex.notify();
        }
    }

    public static void main(String[] args) {
        ThreadB a1 = new ThreadB();
        ThreadB a2 = new ThreadB();
        a1.start();
        a2.start();
        new ThreadB().m1();    
    }

    private void m1() {         
        synchronized (list1) {
            System.out.println(list1.size());
            System.out.println(list2.size());
            try {
                list1.add("hello");
                System.out.println("m1  :::   " + list1.size());
                sleep(5000l);
                System.out.println("Oh mY God");
            } catch (InterruptedException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

        }
    }
}

Output is

0
0
m1  :::   1
Added for 1   2
Added for 2   1
Added for 1   3
Added for 2   2
Oh mY God

After locking list1, how other threads are going to access that list?

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