From a point A on a level ground, the angle of elevation of the top tower is 30º. If the tower is 100 m high, the distance of point A from the foot of the tower is:
Answer is 173 m sin30 = 100 / hyp side
hyp side = 200 Now for distance of point A from the foot of the tower =cos30 * hyp side = 0.866 * 200 = 173 m
Distance from A to bottom of tower=P Height of tower =100m Angle of elevation from point A=30° Therefore Tan 30°=100/P P=100/tan30° =100/(1/√3) =173 So ans is 173m
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 60° and 30° respectively. If the lighthouse is 144 m high, what is the distance between the two ships?
From a point P on a level ground, the angle of elevation of the top tower is 30º. If the tower is 100 m high, Then what is the the distance of point P from the foot of the tower.
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