If we know x + 1/x =2 then what would be the value of x^2048 + 1/x^2048 +x^2047 - 1 / x^2047 + 1/x^2049 - x^2049 +2
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Value of the equation = 4 Solving x+1/x = 2 >> x^2-2x+1 >> x=1 Hence putting value of x in second equation, we get >> 1+1+1-1+1-1+2 = 4.
x + 1/x =2 this is only when x=1. so, x^2048 + 1/x^2048 +x^2047 - 1 / x^2047 + 1/x^2049 - x^2049 +2 =1+1+1-1+1-1+2 =4
x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be
If x + 1/x = 1 then x^(1729) + x^(-1729) = ?