IF
5 - 4 = 23 8 - 1 = 63 6 - 16 = 32 9 - 9 = 78 3 - 9 = 6
Then
3 - 81 = ?
The answer is "0"
the logic is :
sq(5)-sqrt(4)=23
sq(8)-sqrt(1)=63
and so on ..........
sq(3)-sqrt(81)=0
ans=0; how? 5^2-sqrt4=23; 6^2-sqrt16=32; same 3^2-sqrt9=0..
A*A-SQUARE ROOT(B) 5-4=23 (ie) 25-2 8-1=63 (ie)64-1
like wise all so ans is 3-81=9-9=0
(5)^2 - (2)^(1/2) = 25-2=23 simillarly...... 3-81=(3)^2 - (81)^(1/2)=9-9=0
5² - √4 = 25 - 2 = 23 8² - √1 = 64 - 1 = 63 6² - √16 = 36 - 4 = 32 9² - √9 = 81 - 3 = 78 3² - √9 = 9 - 3 = 6
Therefore: 3² - √81 = 9 - 9 = 0
ans is 0 3-81=0. take a square of 3 & square root of 81.
ans=0 because square of ist no.,sqroot of 2nd no. is equal to given no.
Ans - 0 ( a - b ) = square of a- square root of b so 3 -81= 9-9= 0
hey dear friend i think answer will be (3*3=9)-root of 81=0.... so answer will be zero....
square of first - square root of second=0
If 5 - 4 = 23 8 - 1 = 63 6 -16 = 32 9 - 9 = 78 3 - 9 = 6 then 3 - 81 = ?
If 5-4=23, 6-16=32, 9-9=78, 3-9=6 then 3-61=??
3 2 = 7 5 4 = 23 9 9 = 78
3 81 = ??
