If 5 - 4 = 23, 8 - 1 = 63, 6 -16 = 32, 9 - 9 = 78, 3 - 9 = 6 then 3 - 81 = ? [CLOSED]

Question

IF

5 - 4 = 23
8 - 1 = 63
6 - 16 = 32
9 - 9 = 78
3 - 9 = 6

Then

3 - 81 = ?

Answer 1

The answer is "0"

the logic is :

sq(5)-sqrt(4)=23

sq(8)-sqrt(1)=63

and so on ..........

sq(3)-sqrt(81)=0

Answer 2

ans=0;
how?
5^2-sqrt4=23;
6^2-sqrt16=32;
same
3^2-sqrt9=0..

Answer 3

A*A-SQUARE ROOT(B)
5-4=23
(ie) 25-2
8-1=63
(ie)64-1

like wise all
so ans is
3-81=9-9=0

Answer 4

(5)^2 - (2)^(1/2) = 25-2=23
simillarly......
3-81=(3)^2 - (81)^(1/2)=9-9=0

Answer 5

5² - √4 = 25 - 2 = 23
8² - √1 = 64 - 1 = 63
6² - √16 = 36 - 4 = 32
9² - √9 = 81 - 3 = 78
3² - √9 = 9 - 3 = 6

Therefore:
3² - √81 = 9 - 9 = 0

Answer 6

ans is 0
3-81=0.
take a square of 3 & square root of 81.

Answer 7

ans=0
because square of ist no.,sqroot of 2nd no. is equal to given no.

Answer 8

Ans - 0
( a - b ) = square of a- square root of b so 3 -81= 9-9= 0

Answer 9

hey dear friend i think answer will be (3*3=9)-root of 81=0....
so answer will be zero....

Answer 10

square of first - square root of second=0