A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?
Let's length of the train =x meters Speed of the train =y m/sec Then x/y=8 => x=8y Now, (x+264)=y => (8y+264)=20y => y=22 Therefore speed=22m/sec
let the length of the train be x metres and its speed by y m/sec.
Then, x/y = 8 => x = 8y
Now, x + 264 /20= y => 8y + 264 = 20y =>12y=264 =>y=264/12 => y = 22.
So Speed in m/sec= 22 m/sec and Speed in km/hr=22x(18/5) =>79.2km/hr
let train speed= a m/s and length of the train is x m distance=speed*time 1.for telegraph x=a*8 2.for bridge x+264=a*20 put the value of x in second a*8+264=a*20 by solving a=22 m/s
The speed of the train is two more than twice of the time taken to cover 1012 km at uniform speed. What is the ratio of the values of time taken to cover the distance and speed of the train?
A train covers a certain distance at a uniform speed. If the train had been 8 km per hour faster, it would have taken 3 hours less than the scheduled time and if the train was slower by 8 km per hour it would have taken 5 hour more than the schedule time. Find length of the journey.
How many seconds will a 468 m long train take to cross a man driving his motor bike at a speed of 39 km/hr in a direction of the moving train if the speed of the train is 120 km/hr?
