top button
Flag Notify
    Connect to us
      Site Registration

Site Registration

Aarav is two years older than Bhargav who is twice as old as Chetan. If the total of the ages of Aarav, Bhargav.........

+1 vote
447 views

Aarav is two years older than Bhargav who is twice as old as Chetan. If the total of the ages of Aarav, Bhargav and Chetan be 27, the how old is Bhargav?

posted Feb 26, 2016 by Puneet Batra

Share this puzzle
Facebook Share Button Twitter Share Button LinkedIn Share Button

4 Answers

0 votes

Aarav = Bhargav + 2
Bhargav = 2 × chetan

Aarav + Bhargav + Chetan = 27
(Bhargav + 2) + Bhargav + ( Bharagav/2) = 27
Bhargav = 10

answer Feb 26, 2016 by Tejas Naik
0 votes

Let's chetan's age=x
Then Bhargav's age=2x
& Aren't age=2x+2
Now,
x+2x+(2x+2)=27
5x+2=27
x=5
Bhargav's age=2x=2*5=10
Ans:Bhargav's age is 10 yrs.

answer Feb 26, 2016 by Jaikumar Bhatia
0 votes

The answer is 10

answer Apr 15, 2016 by anonymous
0 votes

Bhargav age is 10 years.

In detail:

  1. Assume chetan age is x.
  2. Then bhargav age will be 2x.
  3. Aarav age will be 2x +2

Total age is 27. Hence 5x+2=27. There fore x=5

Bhargav age will be 5*2 = 10 years.

answer Apr 15, 2016 by Katakam Ranjit Kumar



Similar Puzzles
0 votes

Aarav is 7 years older than Bhargav who is twice as old as Sachin.
The total of the ages of Aarav, Bhargav and Sachin is 87.
How old is Sachin?

0 votes

In 2017, A is 9 years older than B who is five times as old as C. The total of the ages of A, B and C is 97 years. What would be the average of A and C ages in the year 2024 ?

0 votes

A is 4 years older than B who is three times as old as C. The total of the ages of A, B and C is 88 years. What is the average of A and C ages?

0 votes

A is 9 years older than B who is six times as old as C. The total of the ages of A, B and C is 139 years. What is the product of A and B ages ?

...