Eight years ago, Sam was eight times the age of his son Sam Jr. Today, if you add their ages together, they add up to 52. How old are Sam and his son?
Today, Sam is 40 years old and his son is 12 years old.
Let X = Sam age and Y = SamJr age 8 years ago , X - 8 = 8 * ( Y - 8) Now X + Y = 52 Solving the two equations, yields X = 40 Y = 12
The sum of the present ages of a father and his son is 60 years. Six year ago, father's age was five times the age of the son. After 6 years, what will be son's age?
The age of a father 10 years ago was thrice the age of his son . Ten years hence, the father's age will be twice that of his son. What is the ratio of their present ages?
The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
A father said to his son, “Two years ago I was three times as old as you; but in fourteen years I shall be only twice as old as you.” What were the ages of each?
