Mr. and Mrs. Jones have three children, all under the age of 20, but none with the same age. Last year, the product of the three ages was 224. This year the product of the three ages is 360 What are the children's ages now?
Ans Children's present age are 5,8 & 9 years. This year, 5*8*9=360 years last year, 4*7*8=224 years
The ages could be 9, 8, 5 Product 9 x 8 x 5 = 360 Previous year 8, 7, 4 8 x 7 x 4 = 224
Child 1 = 8 Child 2 = 9 Child 3 = 5
8x9x5=360 7x8x4=224
LET X, Y, Z be present ages of children Two equations can be written, as follows: (X-1)*(Y-1)*(Z-1) = 224 (1) X*Y+Z = 360 (2) The number 360 can be decomposed as follows: 360 = (2*2*2) * (3*3) * (5) = 8 * 9* 5 By replacing values into equation1, yields: (8-1)* (9-1) * (5-1) = 7*8*4 = 224 Then, the actual ages of children are : 8 years, 9 years and 5 years
The ages of three children added together come to 20 and when multiplied together make 280. If the ages are multiplied together in 10 years time what will the answer be?
Shalu is now two-thirds of Shaina's age. In six years, Shalu will be four-fifths of Shaina's age. In 15 years, Shalu will be seven-eighths as old as sister Shaina. If they are both under the age of ten, how old are they now?
Asha and Lata are sisters. Asha’s age is the two digit number AB, and Lata’s age is the two digit number CD. If you write Lata’s age after Asha’s age, then you get ABCD which is a four digit perfect square. In 11 years Asha will be EF and Lata will be GH. Interestingly, if you repeat the exercise, then the four digit number EFGH is also a perfect square.
What are Asha and Lata’s ages now?
A family, made up of 2 parents with children, has an average age of 20.
If you exclude one parent, who is 40, the average age drops to 15.
How many kids are in the family?
