The ages of three children added together come to 20 and when multiplied together make 280. If the ages are multiplied together in 10 years time what will the answer be?
280 = 2^3 × 5 × 7 = 8 × 5 × 7. 8 + 5 + 7 = 20 After 10 years (8 + 10) × (5 + 10) × (7 + 10) = 18 × 15 × 17 = 4590
Mohan's ages is 1/6 th of his father's age. The father's age will be twice of Suresh's ages, after 10 years. If Suresh's eight birhtday was celebrated 2 years before, what is Mohan's present age?
The age difference between two brothers is 6 years. After 6 years the ratio between the age is 8 : 5. What would be the sum of their present ages?
The sum of the ages of A and B is 63 years. After 6 years, the age of B will be four times that of the A. What is the age of B ?
At present, the ratio between the ages of Arun and Deepak is 3 : 2. After 13 years, Arun's age will be 34 years. What would be the age of Deepak after 8 years from now ?
