Question

A ten digit number is taken in such a way that it is lying between ********** and **********. The last 4 digit of the number are 4 successive digits not necessarily taken in order. Average of these 4 digits is 5.5. On forming a new 4 digit number by taking these 4 digits in reverse order, we find a 4 digit number divisible by 2 but not by 4. The 10 digit number is divisible by 25. Which number would be at hundredth place?

Answer 1

If we take x as the lowest of the 4 consecutive numbers we get

((4x+6)/4)=5.5
X= 4

So the possible combinations are as follows
(Considering the entire 10 digit number is divisible by 25)

4675
6475

Now given that the reverse order of the number is only divisible by 2 and not by 4. So it should be as follows

5746

Because divisibility by 4 is checked by the last two digits we know that the other combination gives numbers divisible by 4.

So the answer is

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