A quantity x varies inversely as the square of y. Given that x = 4 when y = 3, the value of x when y = 6?

Question

S varies directly as R varies and T varies inversely as R varies. At a time R = 20, S = 40 and T = 10. If R is changed to 10, then what will be the value of T ?

Answer 1

x=k/(y*y). From given data 4=k/(3*3) gives k=36
Thus x=36/(y*y)
When y=6, x=36/(6*6) means x=1 answer