How to solve this?? 5+64:4:2x3-0x4

Question

Let A be a 2x3 matrix and B a 3x2 matrix. If AxB and BxA both defined and determinant of the matrix AxB is 4, then evaluate the determinant of the matrix BxA.

Answer 1

ratio is the same as division////

so
according to BODMAS rule,

We start with division.......which is ratio, them multiplication, then addition and lastly......subtraction

64:4:2 gives 64\4\2

which is 32.

0 times 4 is zero, and 32 times 3 is 96

so 5 + 96 gives 101 -0 is 101

so the aNSWER IS 101/

Comments

Why we should not divide first 64 and 4 and then by 2
Then we get a different answer

---

Let's take our ratio has three places...... 64 is in the first place, 4 in the second and 2 in the third place


If you divide 64/4 the answer (which is 16) goes to the first place....

And now you have 16 in the first place and 1/2 in the second......

So you have 16 ÷ 1/2...which is 32.


Remember.....2 is always in the third place.......only its inverse comes to the second place....

---

Thank you
Now I got u

---

64:4:2=16:2=8, NOT 32!

Answer 2

or 5+[2x64/4 = 32x3 = 96 -(0x4 = 0)] = 5+96 = 101

And since 64/4 is divided by 2, you simply place 2 in the numerator and multiply which gives 128.
Rule of thumb: dividing by dividing = multiplying.

Answer 3

5+64:4:2x3-0x4=5+16:2x3-0=5+8x3=5+24=29