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If (3!)^2 - (2!)^1 - (1!)^0 - 3! - 2! - 1! - 0! = 7 + x^2 then x^2 - 3x/2 - 4 = ?

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If
(3!)^2 - (2!)^1 - (1!)^0 - 3! - 2! - 1! - 0! = 7 + x^2
then
x^2 - 3x/2 - 4 = ?

posted Feb 22, 2017 by anonymous

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