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A sample of 0.025 mol of chloride of an element Z was dissolved in distilled water and solution made up to 500cm3...

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A sample of 0.025 mol of chloride of an element Z was dissolved in distilled water and solution made up to 500cm3. 12.5cm3 of this solution reacted with 25cm3 of 0.1 mol dm-3 silver nitrate solution.

What is the most likely formula of chloride?
A) Z2Cl2
B) ZCl
C) ZCl2
D) ZCl4

posted Mar 9, 2017 by anonymous

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1 Answer

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ZCl4

You have 0.025 mol Y.
This is dissolved in 500 cm3 of which you take 12.5 cm3.
Thus you have 0.025 * (12.5 / 500) = 0.000625 mol Y.
There is enough Chloride ions to react with (25 * (0.1 / 1000) =) 0.0025 mol AgNO3.
The reaction stoichiometry is 1 mol chloride ions per mol silver nitrate.
Thus the chloride content per mol Y is: 0.0025 / 0.000625 = 4.
Compound Y is ZCl4.

answer Mar 12, 2017 by Jcm



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