Three dices are thrown simultaneously. What is the probability of getting three numbers whose sum is 13?

Question

A man throws three dices simultaneously on the floor.
What is the probability of getting three numbers whose product is even?

Answer 1

Total number of possibilities = 6 × 6 × 6 = 216
Out comes with thier sum = 13
1. 1,6,6 ===> 6 possibilities
2. 2,5,6 ===> 6 possibilities
3. 3,5,5 ===> 6 possibilities
4. 4,5,4 ===> 6 possibilities
5. 5,4,4 ===> 6 possibilities (should not be counted as they are the same as the previous possibilities)
6. 6,3,4 ===> 6 possibilities
Total possibilities in favour of the required event = 30
Therefore required probability = 30/216 = 13.8889%.