A man throws three dices simultaneously..........What is the probability of getting three numbers whose product is even?

Question

A man throws three dices simultaneously on the floor.
What is the probability of getting three numbers whose product is even?

Answer 1

There are a total of eight possible events here and all but one are in the favour of the required event (Odd*Odd*Odd = Odd)
Therefore the required probability = 7/8.

Answer 2

1- 1/2*1/2*1/2=7/8