x and y are 2 digit numbers where y is obtained by reversing x. If x^2 - y^2 = m^2 then find the value of x+y+m?

Question

x and y are distinct 2 digit numbers such that y is obtained by reversing the digits of x.
Suppose they also satisfy x^2 - y^2 = m^2 for some positive integer m, then find the value of x+y+m?

Answer 1

65^2 - 56^2 = 1089 (x^2 - y^2 = m^2)
and m^0.5 = 33

Comments

The question also told you to add all three integers.
So... 65+56+33=154

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I was so focused on getting the three numbers that I forgot to add them at the end, LOL. :D