A bag has 100 balls out of which there is one green ball. 50 balls are randomly selected. What is probability that the green ball is selected.
P = 99c49/100C50 = 1/2
Explanation P = success cases/all cases All cases = 100C50 Success cases = 1 green ball and any remaining any 49 ball i.e. 99C49
So P=99c49/100C50 = (99!/(49!*50!))/(100!/(50!*50!)) = 1/49!/100/50! = 50/100 = 1/2
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