top button
Flag Notify
    Connect to us
      Site Registration

Site Registration

A is 2 years older than B who is thrice as old as C. Total of ages of A, B and C is 51. What is product of their ages?

0 votes
343 views
A is 2 years older than B who is thrice as old as C. Total of ages of A, B and C is 51. What is product of their ages?
posted Jul 13, 2017 by anonymous

Share this puzzle
Facebook Share Button Twitter Share Button LinkedIn Share Button

1 Answer

0 votes

A = B+2
B = 3C
A + B + C = 51
A + (A-2) + ((A-2)/3) = 51
2A + A/3 = 51 + 2 + (2/3)
7A = 53*3 + 2
A = 161/7 = 23.

Therefore A x B x C = 23 x 21 x 7 = 3381

answer Jul 13, 2017 by Tejas Naik



Similar Puzzles
0 votes

A is 9 years older than B who is six times as old as C. The total of the ages of A, B and C is 139 years. What is the product of A and B ages ?

0 votes

A is 9 years older than B who is four times as old as C. The total of the ages of A, B and C is 49 years. What is the product of ages of A and C?

0 votes

In 2017, A is 9 years older than B who is five times as old as C. The total of the ages of A, B and C is 97 years. What would be the average of A and C ages in the year 2024 ?

0 votes

A is 4 years older than B who is three times as old as C. The total of the ages of A, B and C is 88 years. What is the average of A and C ages?

...