top button
Flag Notify
    Connect to us
      Site Registration

Site Registration

As n increases, the number of positive divisors of nxnxnxn.....n (n times) increases. Is it true or false?

0 votes
375 views

See the following table

Number    Number of positive divisors
1           1
2*2         3
3*3*3       4
4*4*4*4     9 

As n increases, the number of positive divisors of nxnxnxn.....n (n times) increases. Is it true or false?

posted Jul 23, 2017 by anonymous

Share this puzzle
Facebook Share Button Twitter Share Button LinkedIn Share Button

1 Answer

+1 vote
 
Best answer

False

because
5*5*5*5*5 6 (which is less than 9 from n = 4

how???

for 1........divisor is 1, so total 1
for 2*2 = 4 divisors are 1, 2 and 4, so total divisors are 3
for 3*3*3* = 27 divisors are 1,3,9 and 27, so total divisors are 4
for 4*4*4*4 = 256 divisors are 1, 2, 4, 8, 16, 32, 64, 128 and 256, so total divisors are 9

but
for 5*5*5*5*5 = 3125, divisors are 1, 5, 25, 125, 625 and 3125, so total divisors are 6

answer Jul 27, 2017 by Justine Mtafungwa



Similar Puzzles
+1 vote

We are given a positive integer N. Two of its positive divisors are chosen and the differences between N and these two divisors are 270 and 280 respectively.

Find the number of possible value(s) of N?

+1 vote

N has precisely 10 positive divisors.
N has precisely 15 positive divisors.
N has precisely 20 positive divisors.
N has precisely __ positive divisors.

0 votes

We call a positive integer a "good number", if the product of all its divisors equals its cube.

For example, 12 is a good number, because the divisors of 12 are 1, 2, 3, 4, 6, 12, and 1*2*3*4*6*12=1728=12^3.

If n is a good number, what is the minimum number of divisors that n^2 has?

0 votes

N has 3 prime factors.
N^2 has 7!! positive divisors.
N^3 has 10!!! positive divisors.
___ has 13!!!! positive divisors.

0 votes

Find the largest possible value of positive integer N, such that N! can be expressed as the product of (N-4) consecutive positive integers?

...