A is 4 year older than B who s twice as old as C. Total of the ages of A, B and C is 44. What is product of their ages?

Question

A is 4 years older than B who is three times as old as C. The total of the ages of A, B and C is 88 years. What is the average of A and C ages?

Answer 1

A is 4 year older than B ->A=B+4.......1
who s twice as old as C ->B=2C........2
Total of the ages of A, B and C is 44-> A+B+C=44------------3

substitute A,B value
B+4+2C+C=44
B+3C=40...........4

take 2nd and 4th equation
B+3C=40

B-2C=0

C= 8

A=20,B=16,C=8
product of their ages ->A*B*C=2560