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If 5+3=28, 9+1=810, 8+6=214 and 5+4=19 than 7+3=?

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If 5+3=28, 9+1=810, 8+6=214 and 5+4=19 than 7+3=?
posted Aug 13, 2017 by Mohan Singh Chouhan

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4 Answers

+1 vote

410
.
The first digit is the difference between the 2 numbers. The last digit(s) is the sum of the 2 numbers.
5 + 3 = ...
5-3=2 and 5+3=8, thus 5 + 3 = 28
8 + 6 = ...
8-6=2 and 8+6=14, thus 8 + 6 = 214
7 + 3 = ...
7-3=4 and 7+3=10, thus 7 + 3 = 410

answer Aug 13, 2017 by Jcm
0 votes

a+b=(a-b)(a+b)
5+3=(5-3)(5+3)=28
9+1=(9-1)(9+1)=810
8+6=(8-6)(8+6)=214
5+4=(5-4)(5+4)=19
7+3=(7-3)(7+3)=410
Ans is 410

answer Aug 14, 2017 by Jaikumar Bhatia
0 votes

Ans is 410.
First second digit difference is first digit and their addition is next digits.

answer Aug 15, 2017 by Vilas Joshi
0 votes

410 is the answer

answer Aug 22, 2017 by Mogadala Ramana
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