Answer: ********** the last digit of the sum = 5
Explanation:
1^2 + 2^2 + 3^3 ....2017^2 1+4+9+16+25+36+...+n^2=(n(n+1)(2*n+1))/6 1^2 + 2^2 + 3^3 ....2017^2 = (2017(2017+1)(2*2017+1))/6 = **********
Find a five-digit number in which the last number is the sum of the first, second, and third; the third is four less than the last; the fourth is two less than the last; and the first and fourth added are one less than the last. The last number is also three times the second.
Using the digits 1, 2, 3 and 4, find the number of 10-digit sequences that can be written so that the difference between any two consecutive digits is 1.
Examples of such 10-digit sequences are ********** and **********.
