The age difference between two brothers is 6 years. After 6 years the ratio between the age is 8 : 5. What would be the sum of their present ages?
14
x-y=6 ---> (1) (x+6)/(y+6)=8/5 ---> (2) x+y=?
(1) ---> x=y+6 (2) ---> (x+6)/x=8/5 => 5x+30=8x => x=10 => y=4 x+y=10+4=14
The age of a father 10 years ago was thrice the age of his son . Ten years hence, the father's age will be twice that of his son. What is the ratio of their present ages?
The ratio of present ages of Ram and Shyam is 4:3. If 10 years ago Ram was half of Shyam in age, what is the sum of their present ages?
The present ages of A,B and C are in proportions 4:5:6. Eight years ago, the sum of their ages was 66. What is the sum of present age of A and C?
Solve this without paper and pen?
The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
